Question

10. In a simultaneous throw of a pair of dice, find
the probability of getting a number other than 5
on any dice.​

Answer 1

Answer:

25 / 36.

Step-by-step explanation:

In a simultaneous throw :

First dice can any number between and including 1 and 6, and in same manner second can have 6 outcomes.

When both are thrown simultaneously, n of 1st dice may combine with m of 2nd dice. So, the total number of outcomes is 6 x 6 = 36.

Outcomes including 5 are : ( 1 , 5 ) , ( 2 , 5 ) , ( 3 , 5 ) , ( 4 , 5 ) , ( 5 , 5 ) , ( 6 , 5 ) , ( 5 , 1 ) , ( 5 , 2 ) , ( 5 , 3 ) , ( 5 , 4 ) , ( 5 , 6 ).

Total number of outcomes = 11

Total number of outcomes excluding 5 : 36 - 11 = 25

Thus,

= > Probability of getting a number other than 5 = 25 / 36.

Answer 2

Step-by-step explanation:

Aloha !

Favourable outcomes= 11

Total no. of outcomes= 36

Probability= 11/36

Thank you