Question

10. In a triangle, the longest side is double the shortest side and the third side is 3 cm less than the
longest side. If the perimeter of the triangle is 57 cm, find all sides of the triangle.​

Answer 1

Answer:

all sides are 12cm , 24cm , 21cm

Step-by-step explanation:

let the shortest side = x

then, longer side = 2x

and third side = 2x - 3

perimeter = 57 cm

perimeter of triangle = sum of all side

57 = x + 2x + 2x - 3

57 + 3 = 5x

60 = 5x

60/5 = x

12 = x

shortest side = x = 12 cm

longest side = 2x = 24 cm

third side = 2x - 3 = 24 - 3 = 21 cm

Answer 2

Answer:

Three sides are = 12 cm,21 cm and 24 cm respectively

Step-by-step explanation:

Let the shortest side be x

Therefore longest side = 2x (double the shortest)

Thus measurement of third side = 2x - 3 (3 less than longest)

Perimeter is the sum of all sides

Therefore 57 = x + 2x + (2x - 3)

                 57 = 5x - 3

                 5x = 60

Therefore x = 60/5 = 12

Therefore = side 1 (shortest) = x = 12 cm

                    side 2 (longest) = 2x = 12 * 2 = 24 cm

                    side 3  = 2x - 3 = 24 - 3 = 21 cm  

Hope u will get it friend!