Question

10. In a two-digit number, the digit in the units place is twice the digit in the tens place. If 27 is added to
it, digits are reversed. Find the number.​

Answer 1

Kindly refer the attachment..I had already answered the same question for someone else..

Answer 2

Solution-

Let x be the tens digit and y be the unit digit.

Number = 10y + x.

If we reverse the digits, New number = 10x + y (y will be on tens digit and x will be on unit digit).

According to the question,

First condition -

→y = 2x

→ 2x - y = 0......(1)

Second condition -

→ (10+x)−(10x+y) = 27

→ 10y + x - 10x - y = 27

→ 9y - 9x = 27

→ 9(y - x) = 27

→ y - x = 27/3

→ y - x = 3

→ y = 3 + x......(2)

Put the value (2) in (1).

→ 2x - (3 + x) = 0

→ 2x - 3 - x = 0

→ x - 3 = 0

→ x = 3

Now, put x = 3 in (2).

→ y = 3 + 3

→ y = 6

Number = 10x + y

→ Number = 10 (3) + 6

→ Number = 30 + 6

→ Number = 36

Hence, required number is 36.