Question

10. In ∆ABC, D and E are points AC and BC respectively such that DE || AB. If AD = 2x,

BE = 2x – 1, CD = x + 1 and CE = x – 1, then find the value of x.​

Answer 1

Step-by-step explanation:

here, ad/dc = be/ec

thus 2x/x+1 = 2x-1/x-1

therefore 2x(x-1) = (2x-1)(x+1)

hence , 2x^2 -2x =2x^2 +2x-x-1

by solving it further x = -1/3

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hope this is helpful for you

Answer 2

Answer:

Step-by-step explanation: