Question

10. In APQR, ZQ = 90°. If PQ:QR = 1:1, then PQ : PR = (1:2, 1:V2,V2:1)​

Answer 1

Answer:

(i) Given:

PQ = 8 cm

QR = 6 cm

PR = ?

∠PQR = 90°

According to Pythagoras Theorem,

(PR)2 = (PQ)2 + (QR)2

PR2 = 82 + 62

PR2 = 64 + 36

PR2 = 100

∴ PR = √100 = 10 cm

(ii) Given :

PR = 34 cm

QR = 30 cm

PQ = ?

∠PQR = 90°

According to Pythagoras Theorem,

(PR)2 = (PQ)2 + (QR)2

(34)2 = PQ2 + (30)2

1156 = PQ2 + 900

1156 - 900 = PQ2

256 = PQ2

∴ PQ = 16 cm

Answer 2

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