Question

10. In Fig. 10.9, ∠AOB = 90º and ∠ABC = 30º, then ∠CAO is equal to:

(A) 30º (B) 45º (C) 90º (D) 60º​

Answer 1

(D) 60º

∠ ACB=∠AOB=90° ( Angles in the same segment)

In Triangle CAB

∠ C+∠A+∠B=180°

Or, ∠A= 180°-90°-30°=60°

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