Question

10.
In Figure-3, PQ is tangent to the circle with centre at 0, at the point B. If
angle AOB = 100°, then angle ABP is equal to​

Answer 1

Answer:

As OA = OB

Angle OBA = Angle OAB = 40°

SO, Angle ABP = Angle OBP - Angle OBA

= 90° - 40°

Therefore, Angle ABP = 50°

Answer 2

Answer:

50°

Step-by-step explanation:

Let C be any point on major arc AB

Angle ABP = angle ACB........1

Also angle ACB = 1/2 ×AOB......2

from 1 and 2

angle ABP = 1/2 × AOB

= 1/2 × 100

= 50°