Question

10. In given figure, find tanP - cotR.

Answer 1

Step-by-step explanation:

QR = √(15^2 - 12^2) = √81=9

tanP - cotR = 9/12 - 9/12 = 0

Answer 2

Answer:-

$\large\sf{Using\:Pythagoras\:theorem}$

$\longrightarrow$$\small\sf{{PR}^{2}={PQ}^{2}+{QR}^{2}}$

$\longrightarrow$$\small\sf{{(13)}^{2}={(12)}^{2}+{QR}^{2}}$

$\longrightarrow$$\small\sf{169=144+{QR}^{2}}$

$\longrightarrow$$\small\sf{QR=5cm}$

Now, tan P = $\small\sf{\frac{QR}{PQ}=\frac{5}{12}}$

$\small\sf{CotR=\frac{QR}{PQ}=\frac{5}{12}}$

$\small\sf{tan\:P-Cot\:R=\frac{5}{12}-\frac{5}{12}=0}$