Question

10. In given figure maximum power is transferred to
30 9 resistance then
10.15 A
(2) 0.25 A
(3) 0.3 A
(4) 0.5 A​

Answer 1

R (Resistance) = 30 ohm

I (Current) = ? Ampere

V (Potential difference across the resistance of 30 Ohm) = (3+3+3) V = 9 V

We know, V = IR (ohm's law)

So, 9 = I × 30

or, I = 9/30

or, I = 0.3

Therefore, the value of current flowing through the 30 Ohm resistor is 0.3 Ampere .

Answer 2

Explanation:

ans is 0.15 ampere by solving figure you can get it