Question

10. In SABC, 2BCA is a right angle, if Q is the mid point
of the side BC, AC-4 cm and AQ = 5 cm, find (ABY​

Answer 1

Answer:

by Pythagoras Theorem

AQ^2 = QC^2 + AC^2

= 5^2 = QC^2 + 4^2

= 25 = QC^2 +16

= 25 = 9 +16

= QC^2 = 3^2

= QC = 3

SO BC = 3×2 = 6

By Pythagoras theorem

AB^2 = BC^2 + AC^2

= AB^2 = 6^2 + 4^2

AB^2 = 36+16

= AB ^2 = 52

Hope it hy