Question

10. In the adjoining figure ABCD is a rectangle.
find the area of the shaded region​

Answer 1

Answer:

given-length (AD) of the rectangle ABCD

=height (AD) of the triangle ADE=12 cm ,

Height (CF) of triangle CDF=7,

breadth (CD) of the rectangle ABCD = Base (CD) of triangle CDF =18 cm and

base (AE) of triangle ADE=10 cm.

Base (BD) of triangle BEF =18-10=8 cm.

Height (BF) of triangle BEF =12-7 =5.

Area of rectangle ABCD = l×b

=12×18

=216cm2

Area of triangle ADE=1/2×b × h

=1/2×10 ×12

=60cm2

Area of triangle CDF =1/2×b×h

=1/2×18×7

=63cm2

Area of triangle BEF = 1/2×b×h

=1/2×8×5

=20cm2

Area of the shaded region=Area of rectangle-Area of triangle ADE+area of triangle CDF+area of triangle BEF

=216-(60+63+20)

=216-143

=73cm2

Hence,the area of shaded region is 73 cm2 .

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