Question

10. In the figure, AD is the median of traingle ABC. BE and CF are perpendiculars from B and C on AD and AD produced. Prove that BE = CF.​




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Answer 1

Answer:

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Answer 2

Step-by-step explanation:

In ΔBCE & ΔBFC,

1. BC=CB ( Common side)

2. angle BEC= angle CFB=90°( perpendiculars)

3. BF= CE ( mid pt. theorem)

therefore, by S.A.S, ΔBCE congruent to ΔBFC

By C.P.C.T , BE=CF (proved)

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