Question

10. In the figure, O is the centre of
the circle and B is a point of
contact. seg OE 1 seg AD,
AB = 12, AC = 8, find (i) AD
(ii) DC (iii) DE.​

Answer 1

Answer:

AD = 36

DC = 28

DE = 14

Step-by-step explanation:

for AD apply tangent secant formula

and for DC do AD = AC+DC THEN WE WILL GET DC as 28 and as OE is the perpendicular bisector DE=CE THEREFORE DE is half of DC .... PL like my answer