Question

10. In the figure, the curve y = (1 - x)(x + 5) cuts the
x-axis at two points A and B, and the y-axis at the
point C. Find the coordinates of A, B and C.
​

Answer 1

$\underline{\boxed{\bold{Question}}}$

• In the figure, the curve y = (1 - x)(x + 5) cuts the  x-axis at two points A and B, and the y-axis at the  point C. Find the coordinates of A, B and C.

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$\underline{\boxed{\bold{Important \; concepts\;to\;be\;remembered}}}$

➢ Co-ordinates of point on x-axis is of form (x,0)

➢ Co-ordinates of point on y-axis is of form (0,y)

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$\underline{\boxed{\bold{Answer}}}$

Let's Start !

Given Equation ↣ y = (1 - x)(x + 5)

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Now, let's find where this curve cuts x-axis.

At x-axis, y-coordinate of point is zero(0).

Putting y = 0 in given equation

$:\implies y = (1 - x)(x + 5)$

$:\implies 0 = (1 - x)(x + 5)$

$:\implies (1 - x)(x + 5) = 0$

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So,

→ 1 - x = 0

→ x = 1

→ x + 5 = 0

→ x = -5

$\underline{\boxed{\bold{\therefore \; Curve\;cuts\;x-axis\;at\; A(1,0) \; and\;B(-5,0)}}}$

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Now, let's find where this curve cuts y-axis.

At y-axis, x-coordinate of point is zero(0).

Putting x = 0 in given equation

$:\implies y = (1 - x)(x + 5)$

$:\implies y = (1 - 0)(0 + 5)$

$:\implies y = (1 )( 5)$

$:\implies y = 5$

$\underline{\boxed{\bold{\therefore \; Curve\;cuts\;y-axis\;at\; C(0,5)}}}$

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$\underline{\boxed{\bold{\red{\therefore \; Curve\;cuts\;x-axis\;at\;A (1,0) \; and\;B(-5,0)}}}}$

$\underline{\boxed{\bold{\red{\therefore \; Curve\;cuts\;y-axis\;at\; C(0,5)}}}}$

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Hope this helps u.../

【Brainly Advisor】

Answer 2

Answer:

thanks for free points ❤️❤️

because the legend answer to u it is more than enough I think so