Question

10. In the following figure, OA = OC and
AB = BC.
Prove that :
(i) <AOB = 90°
(ii) ∆ AOD = ∆ COD
(iii) AD = CD
​

Answer 1

Answer

i)

∠AOB=∠COB(CPCT)

Let

∠AOB=∠COB=x

x+x=180

2x=180

x=90

∴∠AOB=90

ii)

AO=OC

AD=CD

OD=OD

∴△AOD≅△COD

iii)

In △ABD,△CBD

AB=CB

ABO=CBO

BD=BD

△ABD≅△CBD

∴AD=CD(CPCT)

Answer 2

Answer:

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