10. In the following figure of a ship, ABDH and CEFG are two parallelograms. Find the
value of x.
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In parellelogam abdh,
Angle d =angle bah= 180-130
In parallelogram angle efg
Angle c=agle g angle e =angle gfe =30(opposite angle sum property
Hence triangle cdx
Angle c +angle d+angle x=180
Angle x =180-160=2
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