Question

10. In the following sequence of digits, how many digits
are either immediately preceded by a multiple of 3
or immediately followed by a multiple of 3?
5 3 1 9 332 35 7369 324
(A) 7 (B) 13 (C) 10 (D) 11 (E) 9​

Answer 1

Answer:

the following sequence of digits, how many digits

are either immediately preceded by a multiple of 3

or immediately followed by a multiple of 3?

5 3 1 9 332 35 7369 324

(A) 7 (B) 13 (C) 10 (D) 11 (E) 9

Step-by-step explanation:

make this answer as brainlist

Answer 2

Answer:

13

Step-by-step explanation:

preceded by a multiple of 3 means digit backward should contain multiple of 3 which has follows

31,93,33,32,35,36,69,93,32

Total count =9

immediately followed by a multiple of 3 means digit forward contain multiple of 3 which as follows

53,19,93,33,23,73,36,69,93

Total count =9

now if we add both we get 9+9=18

In question, they asked either - or so we need to remove the common values count from the total count.

so, In both common values are 93,33,36,69,93. and its count is 5

so the answer is 18-5=13