Question

10. In the given figure, a circle inscribed in a triangle
ABC touches the sides AB, BC and CA at points D,
E and F respectively. If AB = 14 cm, BC = 8 cm and
CA = 12 cm. Find the lengths AD, BE and CF.​

Answer 1

Answer:

We know that AD= AF

BD=BE

CE=CF

Let AD= AF=x

BD=BE=y

CE=CF=z

Then x+y=12

y+z=8

x+z=10

On Solving above equation we get x=7,y=5,z=3

So AD=7 , BE=5 , CF= 3

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Answer 2

Answer:

hence AD =7

BE=5

CF=3

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