10. In the given figure, a circle inscribed in a triangle
ABC touches the sides AB, BC and CA at points D,
E and F respectively. If AB = 14 cm, BC = 8 cm and
CA = 12 cm. Find the lengths AD, BE and CF.
Answers
Answered by
2
Answer:
We know that AD= AF
BD=BE
CE=CF
Let AD= AF=x
BD=BE=y
CE=CF=z
Then x+y=12
y+z=8
x+z=10
On Solving above equation we get x=7,y=5,z=3
So AD=7 , BE=5 , CF= 3
Mark me as brainliest plzzz
Answered by
0
Answer:
hence AD =7
BE=5
CF=3
please mark at brainlist friend
Similar questions