Question

10. In the given figure AB = AC, ZA = 42º and ZACD = 14°. The measure of ZBCD=
КА
42
D
149
B.
C С

Answer 1

Answer:

Given,

AB = AC

Hence , Triangle ABC is a isosceles Triangle

Therefore, Angle B = Angle C

Angle A = 42 degree

Angle ACD = 14 degree

Now,

Angle CAB = Angle A + Angle ACD ( EXTERIOR ANGLE PROPERTY)

Angle CAB = 56 degree

Then,

42 degree + Angle B + Angle C = 180 Degree

42 degree + 2 Angle B = 180 degree ( ANGLE B = ANGLE C)

Angle B = 69 degree

Therefore,

Angle B = Angle C

Angle B = Angle ACD + Angle BCD

69 degree = 14 degree + angle BCD

(69 - 14) degree = Angle BCD

55 degree = Angle BCD

Answer 2

Answer:

a) 55° is the correct option pls make as brainlist answer