Question

10. In the given figure,
AB = DB and
AC = DC.
If ZABD = 58°,
ZDBC = (2x - 4),
ZACB = y + 15º and
ZDCB = 63º; find the values of x and y.​

Answer 1

Hello,

Step by step answer:-

In ∆ABC and ∆DBC,

AB=DB(given)

AC=DC(given)

BC=BC(common)

so,∆ABC is congruent to ∆DBC

Therefore,angle ABC=angle DBC(CPCT)

58°=(2x-4)°

2x-4=58

2x=62

x=31°

and angle ACB= angle DCB

(y+15)°=63°

y=63-15

y=48°

hope it helps

plsplsplsplsplsplsplsplsplsplsplspls mark as brainliest

Answer 2

Answer:

Given ,

AB=DB

AC=DC

ABD=58°

DBC=(2x-4)

ACB=y+15

DCB=63°

in triangle ABC and triangle BCD,

AB=DB (given)

AC=DC (given)

BC=BC (common)

this implies that,

triangle ABC is congruent to triangle BCD (SSS rule)

angle DCB = angle ACB

63° = angle ACB

63° = y + 15°

y = 63 - 15 = 48

ABCD IS A PARRELELOGRAM

DIAGONAL BISECTS THE VERTEX ANGLE

58° = 2(2x-4)

2x-4 = 58/2 = 29°

2x = 29+4 = 33

x = 33/2 = 16.5

therefore,

x = 16.5

y = 48

happy to help