Question

10. In the given figure, ABCD is a rhombus, AO = 4 cm and DO = 3 cm. Then the perimeter of the
rhombus is:
D
С
3 cm
A
4 cm
A
(a) 18 cm
(b) 20 cm
(C) 21 cm
(d) 22 cm​

Answer 1

Answer:

ABCD is a rhombus with AO=4cm and DO=3cm.

We know that diagonals of a rhombus are perpendicular to each other.

⇒∠AOD=90∘

Now, in rightangle triangle AOD

AD2=AO2+OD2 by pythagoras theorem

⇒AD2=42+32=16+9=25sq.cm

⇒AD=25cm=5cm

Here perimeter of given rhombus=4×side=4×AD=4×5=20cm.