Question

10. In the given figure, O is the centre of a circle. If ZBAD = 30° and ZABC = 55°, find
(D) ZBAC
(ii) ZABD
А​

Answer 1

Step-by-step explanation:

We know that BD is the diameter of the circle

Angle in a semicircle is a right angle

∠BAD=90

o

Consider △BAD

Using the angle sum property

∠ADB+∠BAD+∠ABD=180

o

By substituting the values

∠ADB+90

o

+35

o

=180

o

On further calculation

∠ADB=180

o

−90

o

−35

o

By subtraction

∠ADB=180

o

−125

o

So we get

∠ADB=55

o

We know that the angle in the same segment of a circle are equal

∠ACB=∠ADB=55

o

So we get

∠ACB=55

o

Therefore, ∠ACB=55

o