Question

10. In the parallelogram ABCD, angleA = 3x - 10 and
angleB = 5x + 30. Find all the angles of the
parallelogram.​

Answer 1

$\LARGE{ \underline{\underline{ \pink{ \bf{ANSWER}}}}}$

The angles of the parallelogram are 50°,130°,50°,130°.

Step-by-step explanation:

》Given

• ∠A = 3x - 10

• ∠B = 5x + 30

》To Find

• The all angles of the parallelogram

》Solution

• Let us assume the name the other angles of the parallelogram as ∠C,∠D.

• We know that ∠A + ∠B = 180° [ Adjacent angles of A parallelogram Supplementary]

• ∠A = 3x - 10

• ∠B = 5x + 30

• So, 3x - 10 + 5x + 30 = 180°

• 8x + 20 = 180

• 8x = 180 - 20

• 8x = 160

• x = 160/8

• x = 20

So, we got x as 20..

So,

• ∠A = 3x - 10 = 3 × 20 - 10 = 50°.

• ∠A = 3x - 10 = 3 × 20 - 10 = 50°.∠B = 5x + 30 = 5 × 20 + 30 = 130°

So,

• ∠C = 50°

• ∠C = 50°∠D = 130°.

Reason :- Opposite Angles of a Parallelogram Are Equal.

☆______________________________☆

Answer 2

Answer:

The angles of the parallelogram are 50°,130°,50°,130°.

Step-by-step explanation:

》Given

∠A = 3x - 10

∠B = 5x + 30

》To Find

The all angles of the parallelogram

》Solution

Let us assume the name the other angles of the parallelogram as ∠C,∠D.

We know that ∠A + ∠B = 180° [ Adjacent angles of A parallelogram Supplementary]

∠A = 3x - 10

∠B = 5x + 30

So, 3x - 10 + 5x + 30 = 180°

8x + 20 = 180

8x = 180 - 20

8x = 160

x = 160/8

x = 20

So, we got x as 20..

So,

∠A = 3x - 10 = 3 × 20 - 10 = 50°.

∠A = 3x - 10 = 3 × 20 - 10 = 50°.∠B = 5x + 30 = 5 × 20 + 30 = 130°

So,

∠C = 50°

∠C = 50°∠D = 130°.

Reason :- Opposite Angles of a Parallelogram Are Equal.

☆______________________________☆

Step-by-step explanation:

@Lv02❤