Question

10. In the PQR, D and E are points on side PQ and PR respectively such that DE!
QR. If PE = 2 cm,PD=3 cm and QD = 4.5 cm then find
DE​

Answer 1

Given :-

• DE || QR .
• PE = 2 cm.
• PD = 3 cm.
• QD = 4.5 cm.

To Find :-

• RE = ?

Solution :-

we know that,

• If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, then the other two sides are divided in the same ratio. { Also called BPT(Basic Proportionality Theorem) } .

since DE || QR .

so,

→ PD/DQ = PE/ER (By BPT)

putting values we get,

→ (3/4.5) = (2/RE)

→ (30/45) = (2/RE)

→ (2/3) = (2/RE)

→ RE = 3 cm (Ans.)

Learn more :-

In ABC, AD is angle bisector,

angle BAC = 111 and AB+BD=AC find the value of angle ACB=?

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