Question

10. In triangle
ABC, the bisector angle A is same as the median through A. triangle
ABC is
(A) isosceles with AB = BC
(B) a right angled triangle
(C) isosceles with AB = AC
(D) isosceles with BC = AC​

Answer 1

Answer:

C) Isosceles with AB=AC

Answer 2

Step-by-step explanation:

For an isosceles triangle angles ABC=ACB=35

Let the angle ADB be x

then ADC is 180-x

as AD is median so BD=CD

and for isosceles triangle AB=AC 

so AB/AC=BD/CD=1

By angle bisector theorem

 BAD=CAD=y  (just take it)

for an triangle BAD 35+x+y=180...(1)

for an triangle DAC 35+180-x+y=180...(2)

35+y=x

therefore  

35+34+y+y=180

2y+70=180

2y=100

y=55

therefore angle BAD=CAD=55

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