Question

10.
In Uttarakhand flood, a family of 10 members contributed the following amounts of money
(in ).
500, 600, 700, 800, 900, 1000, 1100, 1200, 1300, 1400
Find (a) mean contribution, (b) median, (c) mode, (d) range.​

Answer 1

Step-by-step explanation:

Given:-

In Uttarakhand flood, a family of 10 members contributed the following amounts of money

In Uttarakhand flood, a family of 10 members contributed the following amounts of money(in ).

In Uttarakhand flood, a family of 10 members contributed the following amounts of money(in ).500, 600, 700, 800, 900, 1000, 1100, 1200, 1300, 1400.

To find:-

Find (a) mean contribution, (b) median, (c) mode, (d) range.

Solution:-

a)Mean:-

Given observations =500, 600, 700, 800,900, 1000, 1100, 1200, 1300, 1400

Sum of all observations =500+600+700+800+900+1000

+1100+1200+1300+1400=9500

Number of all observations=10

Mean=Sum of all observations/Number of all observations

=>Mean=9500/10

Mean=950

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b)Median:-

Given observations =500, 600, 700, 800,900, 1000, 1100, 1200, 1300, 1400

Number of observations=10 is an even number

=>Median =Average of (n/2) and (n/2)+1 th observations

=>Median=average of 10/2 and (10/2)+1 th observations

=>Median=average of 5th and 6th observations

5th term=900

6th term=1000

Their average =(900+1000)/2

=>1900/2

=>950

Median=950

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c)Mode:-

Given observations =500, 600, 700, 800,900, 1000, 1100, 1200, 1300, 1400

Mode is the frequent occuring observation

There is number occurs more than 1 time

Mode=No

It has no mode

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d) Range:-

Given observations =500, 600, 700, 800,900, 1000, 1100, 1200, 1300, 1400

Heighest observation=1400

Lowest observation=500

Range =Heighest value - Lowest value

=>Range =1400-500

Range =900

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