10 kg of water fall through a height of 480m and all the energy is effecting is heating the water .To what temperature will the water be raised if it was initially at 20 C
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Water is at height (h)=500m.
Potential energy =mgh
=1×9.81×500
=4905J/litre
Specific heat of water =4180J/kgk.
So, E=mcΔT.
4905=1×4180×ΔT
ΔT=
4180
4905
ΔT=1.16
o
C.
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