Question

10. Let A, B,C be complex numbers which are the vertices of an equilateral triangle
Then, we must have:
(A) A+B+C=0
(B) A²+B² + C² = 0
(C) A²+B²+c²+AB+BC+CA = 0
(D) (A-B)² +(B-C)²+(C-A)²= 0.​

Answer 1

A²+B²+c²=0 it is the answer of the above given question