10
let AB & co are the two poles
A B = 18cm, CD = 12m
length of the Rope = AO=?
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According to the problem given ,
Height of the first pole = AB = 18 m
Height of the second pole = CD = 12 m
Length of the wire = AD
AE = AB - BE
= AB - CD
= 18 - 12
AE = 6 m
In ∆ AED ,
< AED = 90° ,
<ADE = 30° ( given )
Sin 30° = AE/AD
1/2 = 6/AD
AD = 6 × 2
AD = 12 m
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