Question

10. Let P = a? - b2 + 2ab, Q=a2 + 4b2-6ab. R=b2 +6, S = a -4ab
T=-2a² + b2 - ab + a. Find P + +R+S-T.​

Answer 1

Answer:

P+Q+R+S-T =4a²+3b²-7ab+6

Step-by-step explanation:

Given ,

P = a²-b²+2ab,

Q = a²+4b²-6ab,

R = b²+6,

S = a-4ab,

T = -2a²+b²-ab+a

Now,

P+Q+R+S-T

= a²-b²+2ab+a²+4b²-6ab+b²+6+a-4ab-(-2a²+b²-ab+a)

= a²-b²+2ab+a²+4b²-6ab+b²+6+a-4ab+2a²-b²+ab-a

= a²+a²+2a²-b²+4b²+b²-b²+2ab-6ab-4ab+ab+a-a+6

= 4a²+3b²-7ab+6

•••♪