10 liter of benzene weight
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Assuming that the conditions are standard conditions of pressure and Temperature( 1atm, 273K)
10L= 10/22.4 moles
10L=0.446moles
Molar mass of Benzene=78
Therefore weight= moles* molar mass
Weight=34.788g
10L= 10/22.4 moles
10L=0.446moles
Molar mass of Benzene=78
Therefore weight= moles* molar mass
Weight=34.788g
Answered by
1
Answer:
mol wt of benzen = 6× 12 + 6× 1 ( h = 1 , c = 12 )
= 72+6=78
at stp 1 mole = 22.4 L
moles in 10L = 10/22.4 = 0.44 mole
if 1 mole = 78g
0.44 mole = 78/.44
= 177.....g
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