Question

10 liters of ideal gas possesses an initial pressure of 100 per square meter at a temperature of 400 Kelvin. if the volume is decreased to 5 liters while raising the temperature to 600 Kelvin, what is the resultant pressure. ​

Answer 1

Correct question:

10 liters of ideal gas possesses an initial pressure of 100 N per square meter at a temperature of 400 Kelvin. if the volume is decreased to 5 liters while raising the temperature to 600 Kelvin, what is the resultant pressure. ​

Given:

• Initial pressure(p1) = 100 N/ m².

• Final pressure(p2) =?

• Initial temperature(T1) = 1000 K

• Final temperature(T2) = 400 K

• Initial volume (v1) = 10 liters

• Final volume(v2) = 5 liters

To find:

The resultant pressure(p2).

Solution:

From the ideal gas law equation we get that,

$\dfrac{p1v1}{T1} = \dfrac{p2v2}{T2}$

Here,

$\dfrac{p1v1}{T1} = \dfrac{p2v2}{T2}$

⇒(100×10)/400 = (p2 ×5)/600

⇒(10/4) = (p2/120)

⇒(p2/120) = (10/4)

⇒ p2 = (10×120/4)

⇒ p2 = (10×30)

⇒p2 = 300 N/m²

So, the resultant pressure is 300 N/m².

Answer:

              The resultant pressure is 300 N/m².