10 litre solution of urea contains 240g urea. The active mass of urea will be
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Active mass of the solution is nothing but molarity
Active mass = Molarity = No of moles of solute/Volume of ssolution in L
No of moles of solute = Given mass in g/ Molecular mass = 240/60 = 4
Active mass = Molarity = 410 = 0.4 M
Active mass = Molarity = No of moles of solute/Volume of ssolution in L
No of moles of solute = Given mass in g/ Molecular mass = 240/60 = 4
Active mass = Molarity = 410 = 0.4 M
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