Question

10 litres of solution of sugar
with 76% water content is
kept in the sun for 5 days.
After 5 days, the water content
in solution remains 20%.
Find the quantity of
remaining solution.​

Answer 1

Step-by-step explanation:

initial amount ofvwater=76% of soln.

= (76/100×10)lt

= 7.6 lt

final amount of water= 20% of soln.

= (20/100×10)lt

= 2 lt

los in water=(7.6-2) lt

= 5.6 lt

now, since sugar amount remains same,

resultant quantity=10lt-5.6lt

= 4.4 lt

Answer 2

Answer:

Amount of sugar in the remaining solution is 4.4liters  

Step-by-step explanation:

Given $10 l$ of sugar solution with 76% water

Amount of water, $\frac{76}{100} \times10=7.6l$

After 5 days, water content in solution remains 20%.

Remained amount of water, $\frac{20}{100} \times10=2l$

Amount of water reduced $=7.6-2= 5.6 l$

Amount of sugar in the remaining solution$=10- 5.6 =4.4l$