10 m long 2 mm diameter steel wire with a mass of 168 kg. What will increase the length of the wire? The value of the Young coefficient of steel. 2.1X 10 ^ 11 Pa
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Answer:
The change in lengthl=
πr
2
Y
FL
where F is weight to be suspended , L=2.0 m is initial length of wire, and r is radius of wire= .5 mm with Y as Young's modulus of material
putting these values we get F=78.5Newton or mass as
9.8
78.5
=8.01kilogram
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GOOD QUESTION
I WILL HELPED HERE GO TO WATCH MY PICTURE AND SOLVE THIS PROBLEM .
MARK AS 5 STAR AND LIKE.
EXPLANATION:
YOUNG'S MODULUS LAW
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