Physics, asked by AditiLohiya, 6 hours ago

10 m/s fixed 37° Find out the distance travelled by the block on incline before it stops.​

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Answered by zikku2005
2

Answer:

u=10m/s;μ=0.5;v=0

N=mgcos37∘

∴mgsin37∘+μN=ma

a=10m/s2 down the incline

Now v2=u2+2as

0=102+2(−10)S

∴S=5m

Hence,the distance travelled by the block on incline before it stops is 5m.

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