10 Masons can dig 20 holes in 40 days. working at the same rate, howmany days will it take for 20 Masons to dig 10 holes
Answers
Answered by
6
Answer:
10 days
Step-by-step explanation:
time taken for 1 masons to dig 1 hole = 10 masons x 40 days / 20 holes
=20 days
total work = 20 masons x 10 holes = 200
time taken to dig the 10 holes for 20 masons is
= 200/20 = 10 days
Answered by
0
Answer:
10days.
Step-by-step explanation:
Given: 10 men can dig 20 holes in 40days
Required : How many days required to dig 10 holes by 20 men?
So let us find out how many man-days required to dig one hole?
To dig 20 holes man days required =10x40=400 man-days
To dig one hole 400/20= 20man-days required.
From above inputs, to dig 10holes the man-days required =10x20=200mandays.
So the days required by 20 men to dig 10 holes=men x days/men = 200/20=10days
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