Question

10. Max is 5 times as old as his son. Five years ago, he was 15 times his son's age. How old will Max be after 7 years?​

Answer 1

Answer:

let present age of max's son is x

max's age=5x

5yrs ago

max's age =15(x-5)

i.e,5x-5=15x-75

10x=70

x=7

max's age is 35

after 7yrs max is 42yrs old

Answer 2

Max's age after 7 years is 42 years

Step-by-step explanation:

Let the present age of son be x

We are give that Max is 5 times as old as his son

Max's age =5x

Son's age 5 years ago = x-5

Max's age 5 years ago = 5x-5

Five years ago, he was 15 times his son's age.

5x-5=15(x-5)

5x-5=15x-75

70=10x

x=7

Max's age =5x=5(7)=35 years

Max's age after 7 years = 35+7=42 years

Hence Max's age after 7 years is 42 years

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