10 men 8 women and 6 boys together can complete a piece of work in 25 days for how many days will 9920 women and 30 boys will be occupied with three times the eve of the work done in a particular time by a Man a Woman a boy are in the ratio 5 is to 3 is to 2
Answers
Answer:
It might help you
Step-by-step explanation:
1 man = 2 women
10 men + 8 women
= (20 + 8) women = 28 women
4 men + 6 women = (8 + 6) women
= 14 women
Given, M1=28,M2=14,D1=5,D2=?
and W1=W2=1
According to the formula,
M1D1W2=M2D2W1
=> 28×5×1=14×D2×1
D2=28×514=10days
Given:
Number of men =10
Number of women =8
Number of boys =6
Number of days for which they work =25
To Find:
how many days will 9920 women and 30 boys will be occupied with three times the eve of the work done in a particular time by a Man a Woman a boy are in the ratio 5 :3 : 2
Explanation:
2 women = 1 man
8 women +10 men
= (20 + 8) women
= 28 women
Now for 4 men + 6 women
= (8 + 6) women
= 14 women
Forming the equation for the given question
we get,
M1=28,
M2=14,
D1=5,
D2=?
and W1=W2=1
According to the formula,
M1D1W2=M2D2W1
=> 28×5×1
=14×D2×1
D2=28×514
=10days
Answer - Number of days = 10Days.