10 men and 15 women finish a work in 6 days. One man alone finishes that work in 100 days that same work. In how many days will a women finish the work?
Answers
Answer:
1 men can finish the whole work in 100 days
Therefore 1 man's 1 days' work = 1/100
=> 10 men's 1 days' work
= 10 × 1/100 = 1/10
Let the time taken by one women to finish the work be x days.
Then, 1 woman's days' work = 1/x
=> 15 women's 1 days' work = 15/x
Given, ( 10 men's + 15 women's ) 1 days' work = 1/6
=> 1/10 + 15/x = 1/6
=> 1/10 + 15/x = 1/6
=> 15/x = 1/6 – 1/10
= 2/30
= 1/15
=> x = 225 days.
Answer: 225 days
Explanation:
Given that
(10M + 15W) x 6 days = 1M x 100 days
=> 60M + 90W = 100M
=> 40M = 90W
=> 4M = 9W.
From the given data,
1M can do the work in 100 days
=> 4M can do the same work in 100/4= 25 days.
=> 9W can do the same work in 25 days.
=> 1W can do the same work in 25 x 9 = 225 days.
Hence, 1 woman can do the same work in 225 days.