Question

10 men and 5 women finish a work in 6 days. One man alone finishes that work in 100 days. In how many days will a women finish the work ?​

Answer 1

$\huge\underline\bold{Answer:-}$

Given,

1 man can finish the whole work in 100 days.

Therefore, 1 man's 1 day's work = 1/100

=> 10 men's 1 day's work = 10 × 1/100 = 1/10

$let \: the \: time \: taken \: by \: one \: women \\ to \: finish \: the \: work \: be \: x \: days.$

Then, 1 woman's 1 day work = 1/x

=> 15 women's 1 day's work = 15/x

Given, ( 10 men's + 15 women's ) 1 day's work = 1/6

$= > \frac{1}{10} + \frac{15}{x} = \frac{1}{6} \\ = > \frac{15}{x } = \frac{1}{6} - \frac{1}{10} \\ = \frac{5 - 3}{30} = \frac{2}{30} = \frac{1}{15}$

$= > x = 225 \: days.$

Therefore, a women will finish the work in 225 days.

Answer 2

Answer:

\Given,

1 man can finish the whole work in 100 days.

Therefore, 1 man's 1 day's work = 1/100

=> 10 men's 1 day's work = 10 × 1/100 = 1/10

\begin{gathered}let \: the \: time \: taken \: by \: one \: women \\ to \: finish \: the \: work \: be \: x \: days.\end{gathered}

letthetimetakenbyonewomen

tofinishtheworkbexdays.

Then, 1 woman's 1 day work = 1/x

=> 15 women's 1 day's work = 15/x

Given, ( 10 men's + 15 women's ) 1 day's work = 1/6

\begin{gathered}= > \frac{1}{10} + \frac{15}{x} = \frac{1}{6} \\ = > \frac{15}{x } = \frac{1}{6} - \frac{1}{10} \\ = \frac{5 - 3}{30} = \frac{2}{30} = \frac{1}{15} \\\end{gathered}

=>

10

1

+

x

15

=

6

1

=>

x

15

=

6

1

−

10

1

=

30

5−3

=

30

2

=

15

1

= > x = 225 \: days.=>x=225days.

Therefore, a women will finish the work in 225 days.}}}}