10 men and 8 women can together complete a work in 5 days. Work done by a woman is equal to the half of the work done by a man. In how many days, will 4 men and 6 women complete that work?
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According to the question,
1 man = 2 women
10 men + 8 women
= (20 + 8) women = 28 women
4 men + 6 women = (8 + 6) women
= 14 women
Given, M1=28,M2=14,D1=5,D2=?
and W1=W2=1
According to the formula,
M1D1W2=M2D2W1
=> 28×5×1=14×D2×1
D2=28×514=10days
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