10 men can complete a job in 200 days. They started the work. After 20 days, 10 men with three times their efficienc
joined them. The total time (in days) to complete the remaining job is:
Options :
1 60
2 63
3 68
4 70
Answers
Answer:
60
Explanation:
10 men is equal to 200 days
1 man is equal to = 10*180
10 man three time effective = 1*180/30=60
so, 60 days ans
45 Days required to complete remaining job
Step-by-step explanation:
10 men can complete a job in 200 days
=> 10 men 1 Day work = 1/200
=> 1 Man 1 Day work = 1/2000
10 Men 20 days Works = 20/200 = 1/10
Remaining work = 1 - 1/10 = 9/10
10 men with three times their efficiency joined them
1 Man with 3 times efficiency 1 day work = 3/2000
10 men with 3 times efficiency 1 day work = 10 * 3/2000 = 3/200
Now 20 men 1 Day work = 1/200 + 3/200 = 4/200 = 1/50
Remaining Work = 9/10
Number of Days required = (9/10)/(1/50)
= 45
45 Days required to complete remaining job
Learn more:
B can complete the work in 30 days, if A is 50% more efficient than B ...
https://brainly.in/question/13689086
The efficiencies of A, B & C are in the ratio of 2:3:5. Working ...
https://brainly.in/question/12223267