Question

10 men can complete a work in 12 days.12 women can complete a same work in 20 daus. if 8 men and 10 women work for 6 days.how much work will be left after 6 days​

Answer 1

Explanation:

10 men one day work =1/12

1 men one work =1/(10*12)= 1/120

same way 1 woman one day work = 1/240

8 men one day work = 8/120= 1/15

10 woman one day work =10/240= 1/24

both 8men and 10 woman one day work = (1/15)+(1/24) = (8+5)/120 = 13/120

so six days work = 6*13/120= 78/120

so remaining work = 1-78/120 =42/120

= 14/40= 7/20

so (7/20) part will be remaining