Math, asked by sangita66, 5 months ago

10 men ,working for 6days of 10 hours each, finish 5/21 of a piece of work. how many men working at the same rate and for the same number of hours each day, will be required to complete the work in 8 days ​

Answers

Answered by anudeepko046
2

Answer:

24 mens

Step-by-step explanation:

Here time and capacity is same so we will not consider them

10 men complete 5/21 work in 6 days Means 1 man will complete 5/21 work in 60 days

1 man complete whole work in 60*21/5 = 252 days

To finish work in 192 days, man required = 1 to finish work in 1 days ,

men required = 192 to finish work in 8 days

men required = 192/*8

= 24 men

hope it helps you

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