Question

(10) Mention any one condition under which a second order reaction of rate law:
rate = k[A] [B]'
can be made a pseudo first order reaction.​

Answer 1

Answer:

hydrolysis of ester

Explanation:

CH3COOCH3+H2O ----->CH3COOH+ CH3OH

RATE=[CH3COOCH3] [H2O]

In this reaction if H2O is taken in excess, the change in concentration of [H2O] is so small so we can neglect that and rate becomes

RATE=[CH3COOH]

Hence a second order reaction is made into a pseudo first order reaction