Question

-10 microcoulombs 40 microcoulombs and q are the charges on the three identical spherical conductors p q and R respectively now P and Q attract each other with a force f when they are separated by a distance D now p and q are made in the contact with each other and then separated again q and R are touched and they are separated by the distance the repulsive force between q and R is 4 then the charge Q is options
1)10micro coulomb
2)30micro coulomb
3)40 micro coulomb
4)65 micro coulomb

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Answer 1

As per the question, we know that;

-10 μC, 40 μC, and q are the charges on three particular conductors, i.e. P, Q, and R; along with Distance = d

Now, it is said that P and Q are brought into constant with each other but are later separated. Again Q and R are to undergo the same procedure of contact and separation; while the distance remains to be d;

So,

$F = \frac{10 * 40}{r^2} K = \frac{400}{r^2} K = \frac{400}{d^2} K$...(Eqn. 1) (∵ r² = d²)

Then,

$4F = \frac{40q}{d^2} K$

On putting the value of Eqn. 1 in the above equation, we get;

$4 * \frac{400K}{d^2} = \frac{40q}{d^2} K$

⇒ $q = \frac{400 * 4}{40} = 40$ (∵ $K$ and $d^2$ gets struck out)

∴ the value of charge $q$ = (40 - 10) μC = 30 μC

Ans) (2) 30 micro coulomb

Answer 2

Answer:

65 coloumb

Explanation:

When P and Q come in contact with each other charge transfer takes place, Now net charge on P and Q will be