Question

10 microfarad capacitor is charged to a potential of 100V it is then connected to another uncharged capacitor .The common potentianl reached is 40V. capacitance of the capacitor is​

Answer 1

Given:

10 microfarad capacitor is charged to a potential of 100V. It is then connected to another uncharged capacitor .The common potential reached is 40V.

To find:

Capacitance of the uncharged Capacitor

Calculation:

Since there is no loss of charge while connecting the second uncharged Capacitor, we can say that common potential V is ;

$\therefore \: V = \dfrac{C1V1 + C2V2}{C1 + C2}$

Putting available values ;

$= > 40 = \dfrac{(10 \times 100) + ( C\times 0)}{10 +C }$

$= > 40 = \dfrac{(10 \times 100) + 0}{10 +C }$

$= > 40 = \dfrac{1000}{10 +C }$

$= > 400 + 40 C= 1000$

$= > 40 C= 600$

$= > C= 15 \: \mu F$

So, final answer is

$\boxed{ \sf{ \large{ C= 15 \: \mu F}}}$