Question

10 milli equivalents of solute is present in 5ml of an aqueous solution. then it's normality is

Answer 1

Hey dear,

★ Normality -
It's expressed as the number of equivalents of solute per liter of solution.

◆ Answer- 2 N

● Explaination-
# Given-
Gram eqivalents of solute = 10 miliequi. = 10^-2 equi.
Volume of solution = 5 ml = 5×10^-3 l

# Solution-
Normality = gram eqivalents of solute / volume of solution
Normality = 10^-2 / 5×10^-3
Normality = 2 N

Normality of given soln is 2 N.

Hope this helps...

Answer 2

Answer:

SOLVD

Explanation:

IN PICC