10 ml HCl solution produced 0.1435g of AgCl when treated with excess silver nitrate solution. What is the molarity of acid solution
Answers
Answered by
9
Answer:
➡HCl + AgNO3 …............>AgCl+ HNO3
➡10ml …...excess .... ….............0
➡0ml …..excess.. …..................0.1435g
➡...................................................=(0.1435/143.5) mol
=0.001mol AgCl made by 10 ml of HCl
From reaction it is clear that,
➡1 mole of AgCl would be obtained by1 mole HCl
➡So number of moles of HCl in 10ml would be=0.001
➡SO number of equivalents of HCl in 10ml = 0.001*1 …..(as basicity of HCl =1)
➡Hence normality of HCl=(number of equivalents of HCl/volume of HCl in ml)*1000
normality= (0.001/10)*1000=0.1N
Similar questions