Question

10 ml HCl solution produced 0.1435g of AgCl when treated with excess silver nitrate solution. What is the molarity of acid solution

Answer 1

Answer:

➡HCl + AgNO3 …............>AgCl+ HNO3

➡10ml …...excess .... ….............0

➡0ml …..excess.. …..................0.1435g

➡...................................................=(0.1435/143.5) mol

=0.001mol AgCl made by 10 ml of HCl

From reaction it is clear that,

➡1 mole of AgCl would be obtained by1 mole HCl

➡So number of moles of HCl in 10ml would be=0.001

➡SO number of equivalents of HCl in 10ml = 0.001*1 …..(as basicity of HCl =1)

➡Hence normality of HCl=(number of equivalents of HCl/volume of HCl in ml)*1000

normality= (0.001/10)*1000=0.1N